Textbook Question
Calculate the derivative of the following functions.
y = csc ex
Ch. 3 - Derivatives
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243
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Table of contents
- Ch. 1 - Functions210
- Ch. 2 - Limits371
- Ch. 3 - Derivatives633
- Ch. 4 - Applications of the Derivative412
- Ch. 5 - Integration328
- Ch. 6 - Applications of Integration331
- Ch. 7 - Logarithmic, Exponential Functions, and Hyperbolic Functions177
- Ch. 8 - Integration Techniques394
- Ch. 9 - Differential Equations179
- Ch. 10 - Sequences and Infinite Series339
- Ch. 11 - Power Series218
- Ch.12 - Parametric and Polar Curves215
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 3, Problem 34a
Derivatives and tangent lines
a. For the following functions and values of a, find f′(a).
f(x) = x²; a=3
Verified step by step guidance1
Step 1: Understand the problem. We need to find the derivative of the function f(x) = x^2 and then evaluate it at a specific point, a = 3.
Step 2: Find the derivative of f(x) = x^2. The derivative, denoted as f'(x), is found using the power rule. The power rule states that if f(x) = x^n, then f'(x) = nx^(n-1).
Step 3: Apply the power rule to f(x) = x^2. Here, n = 2, so f'(x) = 2x^(2-1) = 2x.
Step 4: Evaluate the derivative at the given point a = 3. Substitute x = 3 into the derivative f'(x) = 2x to find f'(3).
Step 5: Simplify the expression obtained in Step 4 to find the value of f'(3).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Derivatives
A derivative represents the rate of change of a function with respect to its variable. It is defined as the limit of the average rate of change of the function as the interval approaches zero. In practical terms, the derivative at a point gives the slope of the tangent line to the function at that point.
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Derivatives
Tangent Lines
A tangent line to a curve at a given point is a straight line that touches the curve at that point without crossing it. The slope of the tangent line is equal to the derivative of the function at that point. This concept is crucial for understanding how functions behave locally around specific values.
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Function Evaluation
Function evaluation involves substituting a specific value into a function to determine its output. In the context of derivatives, evaluating the function at a point helps in calculating the derivative at that point. For example, to find f′(3) for f(x) = x², one must first understand how to compute f(3) and then apply the derivative formula.
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Related Practice
Textbook Question
Derivatives and tangent lines
b. Determine an equation of the line tangent to the graph of f at the point (a,f(a)) for the given value of a.
f(x) = x²; a=3
Textbook Question
Based on sales data over the past year, the owner of a DVD store devises the demand function D(p) = 40 - 2p, where D(p) is the number of DVDs that can be sold in one day at a price of p dollars.
For what prices is the demand elastic? Inelastic?
Textbook Question
Find the derivative function f' for the following functions f.
f(x) =3x²+2x−10; a=1
Textbook Question
Based on sales data over the past year, the owner of a DVD store devises the demand function D(p) = 40 - 2p, where D(p) is the number of DVDs that can be sold in one day at a price of p dollars.
Find the elasticity function for this demand function.
Textbook Question
Calculate the derivative of the following functions.
y = tan ex