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Ch. 11 - Power Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 11, Problem 11.4.46

Approximating real numbers Use an appropriate Taylor series to find the first four nonzero terms of an infinite series that is equal to the following numbers.
√e

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Recognize that \( \sqrt{e} \) can be rewritten as \( e^{1/2} \). This allows us to use the Taylor series expansion for \( e^x \) centered at \( x = 0 \).
Recall the Taylor series expansion for \( e^x \) about 0 is given by: \[ e^x = \sum_{n=0}^{\infty} \frac{x^n}{n!} = 1 + x + \frac{x^2}{2!} + \frac{x^3}{3!} + \cdots \]
To find the series for \( e^{1/2} \), substitute \( x = \frac{1}{2} \) into the series: \[ e^{1/2} = 1 + \frac{1}{2} + \frac{(1/2)^2}{2!} + \frac{(1/2)^3}{3!} + \cdots \]
Calculate each term up to the first four nonzero terms without simplifying the numerical values completely, so the terms are: \[ 1, \quad \frac{1}{2}, \quad \frac{(1/2)^2}{2!}, \quad \frac{(1/2)^3}{3!} \]
Write the first four nonzero terms of the infinite series as the approximation for \( \sqrt{e} \): \[ \sqrt{e} \approx 1 + \frac{1}{2} + \frac{1}{8} \cdot \frac{1}{2} + \frac{1}{16} \cdot \frac{1}{6} + \cdots \] (You can leave the terms in factorial and power form to keep the expression clear.)

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Taylor Series Expansion

A Taylor series represents a function as an infinite sum of terms calculated from the function's derivatives at a single point. It approximates functions near that point, allowing complex expressions to be expressed as polynomials. Understanding how to construct and use Taylor series is essential for approximating values like √e.
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Taylor Series

Function Composition and Substitution in Series

To find the Taylor series of a composite function like √e, one often rewrites the expression in a form suitable for expansion, such as √(e) = (e^x)^(1/2). Substituting variables and manipulating the function helps apply known series expansions effectively, enabling the extraction of the first few nonzero terms.
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Geometric Series

Binomial Series Expansion

The binomial series generalizes the expansion of expressions like (1 + x)^r for any real exponent r. It is particularly useful for functions involving roots or fractional powers, such as square roots. Using the binomial series allows the approximation of √(1 + x) and is key to finding the terms of the series for √e.
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Geometric Series
Related Practice
Textbook Question

{Use of Tech} Newton's derivation of the sine and arcsine series Newton discovered the binomial series and then used it ingeniously to obtain many more results. Here is a case in point.

a. Referring to the figure, show that x = sin s or s = sin ⁻¹ x.

b. The area of a circular sector of radius r subtended by an angle θ is 1/2r²θ. Show that the area of the circular sector APE is s/2, which implies that

s = 2 ∫₀ˣ √(1 − t²) dt − x √(1 −x²)

c. Use the binomial series for f(x) = √(1 − x²) to obtain the first few terms of the Taylor series for s=sin ⁻¹ x.

d. Newton next inverted the series in part (c) to obtain the Taylor series for x=sin s. He did this by assuming sin s = ∑ aₖ sᵏ and solving x = sin(sin ⁻¹ x) for the coefficients aₖ. Find the first few terms of the Taylor series for sin s using this idea (a computer algebra system might be helpful as well).

Textbook Question

Limits Evaluate the following limits using Taylor series.

lim ₓ→∞ x(e¹/ˣ − 1)

Textbook Question

Radius and interval of convergence Determine the radius and interval of convergence of the following power series.


∑ₖ₌₁∞ (kx)ᵏ

Textbook Question

Suppose f(0)=1, f'(0)=0, f''(0)=2, and f⁽³⁾(0)=6. Find the third-order Taylor polynomial for f centered at 0 and use it to approximate f(0.2).

Textbook Question

Does the accuracy of an approximation given by a Taylor polynomial generally increase or decrease with the order of the approximation? Explain.

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Textbook Question

Limits Evaluate the following limits using Taylor series.

lim ₓ→₄ (x² 16)/(ln (x 3)}

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