Textbook Question
11–86. Applying convergence tests Determine whether the following series converge. Justify your answers.
∑ (from k = 1 to ∞) 5ᵏ(k!)² / (2k)!
Ch. 10 - Sequences and Infinite Series
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243
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Table of contents
- Ch. 1 - Functions210
- Ch. 2 - Limits371
- Ch. 3 - Derivatives633
- Ch. 4 - Applications of the Derivative412
- Ch. 5 - Integration328
- Ch. 6 - Applications of Integration331
- Ch. 7 - Logarithmic, Exponential Functions, and Hyperbolic Functions177
- Ch. 8 - Integration Techniques394
- Ch. 9 - Differential Equations179
- Ch. 10 - Sequences and Infinite Series339
- Ch. 11 - Power Series218
- Ch.12 - Parametric and Polar Curves215
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 10, Problem 10.8.57
11–86. Applying convergence tests Determine whether the following series converge. Justify your answers.
∑ (from k = 1 to ∞)5¹⁻²ᵏ
Verified step by step guidance1
Identify the given series: \( \sum_{k=1}^{\infty} 5^{1 - 2k} \). Notice that the general term can be rewritten to better understand its form.
Rewrite the term \( 5^{1 - 2k} \) as \( 5^{1} \cdot 5^{-2k} = 5 \cdot (5^{-2})^{k} \). This shows the series is a geometric series with common ratio \( r = 5^{-2} = \frac{1}{25} \).
Recall the convergence criterion for a geometric series: it converges if and only if \( |r| < 1 \). Since \( \frac{1}{25} < 1 \), the series converges.
To justify convergence, state that because the absolute value of the common ratio is less than 1, the infinite sum converges to \( \frac{a}{1 - r} \), where \( a \) is the first term of the series.
Find the first term \( a = 5^{1 - 2(1)} = 5^{-1} = \frac{1}{5} \) and express the sum formula for the series as \( S = \frac{a}{1 - r} = \frac{\frac{1}{5}}{1 - \frac{1}{25}} \), which confirms the series converges and allows calculation of its sum.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Geometric Series
A geometric series is a series where each term is obtained by multiplying the previous term by a constant ratio. It has the form ∑ ar^k, and its convergence depends on the absolute value of the ratio r. If |r| < 1, the series converges; otherwise, it diverges.
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Geometric Series
Convergence Tests
Convergence tests are methods used to determine whether an infinite series converges or diverges. For geometric series, the ratio test or direct recognition of the ratio can be applied. Understanding these tests helps justify the behavior of the series.
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Exponential Expressions and Simplification
Simplifying exponential expressions is crucial to identify the common ratio in a series. Rewriting terms like 5^(1-2k) helps express the series in a standard geometric form, making it easier to analyze convergence.
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Related Practice
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Textbook Question
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