Compute sec(π/3).

List all vertical asymptotes of y = csc((π/4) x) in the closed interval [0,8].

For y = sec(2x - π), compute the period and find the vertical asymptotes closest to x = 0 (give the two asymptotes that straddle the origin).

For the function y = csc(x/2), what is the fundamental period and what is the spacing between consecutive vertical asymptotes?

Consider y = sec(x). Now form g(x) = sec(3x) + 2. Does adding +2 change the locations of vertical asymptotes?