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Multiple Choice
Evaluate the given logarithmic expression.
A
B
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D
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1
Recognize that the expression is \( \log_2 128 \), which asks: "To what power must 2 be raised to get 128?"
Express 128 as a power of 2. Since 128 is a power of 2, write it in the form \( 2^x = 128 \).
Find the exponent \( x \) such that \( 2^x = 128 \). This means determining the value of \( x \) where 2 multiplied by itself \( x \) times equals 128.
Use the property of logarithms that \( \log_b b^x = x \) to conclude that \( \log_2 128 = x \).
Therefore, the value of \( \log_2 128 \) is the exponent \( x \) found in step 3, which is the solution to the problem.